if you are using 657.0 grams of oxygen gas to react with calcium how many gram of calcium oxide will u product

The amount in grams of CaO that will be produced is 2,302.67824 grams

Explanation:

The reaction between calcium and oxygen to produce calcium oxide (quicklime) can be presented as follows;

2Ca (s) + O₂ (g) → 2CaO (s)

From the above chemical equation, we have;

2 moles of calcium, Ca, react with 1 mole of oxygen gas, O₂, to produce 2 moles of CaO

With the assumption that there is an excess amount of Ca, we have;

The molar mass of O₂ = 32 g/mol

The number of moles, 'n', of O₂ in 657.0 grams of oxygen is therefore;

The number of moles of a substance =  Mass of substance/(Molar mass of substance)

∴ n = 657.0 g/(32 g/mol) = 20.53125 moles

The number of moles of O₂ in the 657.0 grams of oxygen present in the reaction, n = 20.53125 moles

1 mole of O₂ produces 2 moles of CaO, therefore, 20.53125 moles of oxygen will produce 2 × 20.53125 or 41.0625 moles of CaO

The molar mass of CaO = 56.0774 g/mol

Therefore, the mass of 41.0625 moles of CaO is given as follows;

Mass of substance = (The number of moles of a substance) × (Molar mass of substance)

The mass of CaO produced = 41.0625 moles × 56.0774 g/mol = 2,302.67824 g.