Chemistry, 08.02.2021 07:50 kuehnkeegan

The following data was collected when a reaction was performed experimentally in the laboratory. Determine the maximum amount of Fe that was produced during experiment. Explain how you determine this amount. (5 points)

The following data was collected when a reaction was performed experimentally in the laboratory.

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Answer from: carter4026

5 moles

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

Fe₂O₃ + 2Al —> Al₂O₃ + 2Fe

From the balanced equation above,

1 mole of Fe₂O₃ reacted with 2 moles of Al to produce 2 moles of Fe.

Next, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 mole of Fe₂O₃ reacted with 2 moles of Al.

Therefore, 3 moles of Fe₂O₃ will react with = 2 × 3 = 6 moles of Al.

From the calculation made above, we can see that a higher amount (i.e 6 moles) of Al than what was given (i.e 5 moles) is needed to react completely with 3 moles of Fe₂O₃.

Therefore, Al is the limiting reactant and Fe₂O₃ is the excess reactant.

Finally, we shall determine the maximum amount Fe produced from the reaction.

Here, the limiting reactant will be use because all of it is consumed by the reaction.

The limiting reactant is Al and the maximum amount of Fe produced can be obtained as follow:

From the balanced equation above,

2 moles of Al reacted to produce 2 moles of Fe.

Therefore, 5 moles of Al will also react to produce 5 moles of Fe.

Thus, the maximum amount of Fe produced is 5 moles.

Answer from: Quest

the dissociation of nickel hydroxide is follows:

$ni(oh)_2 > ni^2^+ + 2 oh^-$

$ksp for no(oh)2 = 5.5 * 10^-^1^6$

$5.5 * 10^-^1^6 = s * (2 s)^2 = 4 s^3$

$s^3 = 137.5 * 10^-^1^8$

$s = 5.14 * 10^-^6 = [oh^-]$

the concentration of hydroxide ion is

$5.14 * 10^-^6 = [oh^-]$

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

$k = [ ni^2^+] * [oh^-]^2$

$6.1 * 10^-^1^6 = [ ni^2] * [5.14 * 10^-^6]^2$

$[ ni^2^+] = 0.23 * 10^-^4 mol /l$

thus, concentration of ni is 0.23 * 10^-^4 mol /l

Answer from: Quest

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.

for example, fusion of hydrogen atoms at the sun.

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.

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The following data was collected when a reaction was performed experimentally in the laboratory. De...