Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels selectively permeable only to chloride ions. The left compartment (also called inside) contains 1 mM Cl- and the right compartment (also called outside) contains 100 mM Cl-. What will the electrical potential be when the system attains equilibrium

This question is incomplete, the complete question is;

Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels selectively permeable only to chloride ions. The left compartment (also called inside) contains 1 mM Cl- and the right compartment (also called outside) contains 100 mM Cl-. What will the electrical potential be when the system attains equilibrium? [ assume body temperature; log 100 = 2, log 10 = 1, log 1 = 0, log 0.1 = -1, log 0.01 = -2]

Options;

a) -62 mV

b) -124 mV

c) +62 mV

d) 0 mV

e) +124 mV

the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

Explanation:

Given the data in the question;

Two compartments are divided by lipid bilayer;

In inside compartment Cl- ion concentration- 1mM and out side of the cell concentration is 100mM

now we apply the Nernst equilibrium potential equation;

Chlorine ion valency is z = –1

So

= 62/z × log(ion outside/ ion inside) [for Cl‐ ions]

= (62 / –1) x log(  100 / 1 )

  = -62 x 2 =

 = –124mV

Therefore, the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

i'm assuming that the correct answer is indeed the first one/ "a"..