If 0.332 mol of zinc reacts with excess lead(IV) sulfate, how many grams of zinc sulfate will be produced in the reaction?

53.6 g

Explanation:

Step 1: Write the balanced equation

2 Zn + Pb(SO₄)₂ ⇒ 2 ZnSO₄ + Pb

Step 2: Calculate the moles of ZnSO₄ produced from 0.332 moles of Zn

The molar ratio of Zn to ZnSO₄ is 2:2. The moles of ZnSO₄ produced are 2/2 × 0.0332 mol = 0.0332 mol.

Step 3: Calculate the mass corresponding to 0.332 moles of ZnSO₄

The molar mass of ZnSO₄ is 161.44 g/mol.

0.332 mol × 161.44 g/mol = 53.6 g

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