500.0 mL of a gas is collected at 745 K. What will the volume be at standard temperature?

183.22mL

Explanation:

Using Charles law equation, which is as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

T1 = initial temperature (K)

V2 = final volume (mL)

T2 = final temperature (K)

Note that standard temperature of a gas is 273K.

Hence, based on the provided information, V1 = 500.0mL, T1 = 745K, V2 = ?, T2 = 273K

Using the formula; V1/T1 = V2/T2

500/745 = V2/273

Cross multiply

V2 × 745 = 500 × 273

745V2 = 136500

V2 = 136500/745

V2 = 183.22

At standard temperature (273K), the new volume will be 183.22mL.

183 ml

Explanation:

yes

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