What are the relative energy levels of the three staggered conformations of 2,3-dimethylbutane when looking down the C2―C3 bond? Conformation: A and B are equal energy, and C is the lowest energy conformation C is the highest energy conformation and A is the lowest (energy level of B is in between the two) A is the highest energy conformation and C is the lowest (energy level of B is in between the two) A and B are equal energy, and C is the highest energy conformation B is the highest energy conformation and C is the lowest (energy level of A is in between the two)

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

pv=nrt

explanation: