HW: Percent Composition You MUST show your work to receive credit!!! (try to explain step-by-step plz)
1. How many particles are present in a 56.9 mole sample of calcium hydroxide?

2. How many particles are present in a 121.75 gram sample of NaCl?

3. What is the percent composition of nitrogen in copper (I) nitrate, CuNO 3 ?

4. What is the mass percentage of magnesium in magnesium chloride?

5. How many particles are present in a 84 gm of sample of Barium hydroxide?

6. How many particles are present in a 125 gram sample of sulfur dioxide?

7. What is the percent composition of Magnesium in Magnesium Phosphate?

8. What would be the volume of 250 gm of Nitrogen gas?

What’s the question

Show and image of the mixtures or write them

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.