How many grams of H2 will react with 350 g of N2?

10.80

Explanation:

As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen  reacts with 1 mol of hydrogen.

In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.

We can set up the ratio;

28.01 g of

l

N

2

needs  

6.048 g of

l

H

2

1 g of

l

N

2

needs  

6.048

28.01

g  of

l

H

2

50.0 g of

l

N

2

needs  

6.048

×

50.0

28.01

l

g of

l

H

2

=

10.80 g of

l

H

2

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.