Compare the two structural formulas in each set. Do they represent the same compound, represent constitutional isomers or represent two compounds which are neither identical nor constitutional isomers

(1). Both compounds are constitutional isomers.

(2). Both Compounds are constitutional isomers.

(3). Both compounds are identical isomers.

Explanation:

NB: Kindly check the attached picture for the diagram paired compounds.

The term 'constitutional isomers' means the isomers with the same molecular formula, the only difference is the way they are arrange. Constitutional isomers have the same number of elements in them, only their arrangements differs.

Constitutional isomers is also known as structural isomers and it is one of the types of isomers. The other one is stereo-isomers or spartial isomers which is also further divided.

Now, let's consider the paired chemical compounds.

(1). Both compounds are constitutional isomers.

Deduction: this are functional isomers as what differs is the arrangement of the C=O group.

(2). Both Compounds are constitutional isomers.

Deduction: the OH group is in the same position. Only the arrangement of carbon differs.

(3). Both compounds are identical isomers.

C) the increase in atmospheric pressure pushes the walls of the balloon outward thus making it  is the answer.hope i you.

Note that 2 mol dm⁻³ = 2 mol/(dm³)outline: we're given the concentration of hcl, which is  2 mol dm⁻³ (cubic meters in the denominator can represent volume, so i know this is concentration). we're an amount of calcium carbonate caco₃, which is 5 g. we're presented with a chemical equation which includes caco₃ and hcl. we are told to find the volume of hcl. from what we see so far, this seems to be a stoichiometry  problem. we'll have to use the given information about calcium carbonate to find the amount of moles of hcl needed to fully react with calcium carbonate. then we'll have information about the moles of hcl and the concentration of hcl; that will be enough to figure out volume according to the formula concentration = moles / volume.======all the answer choices are not in dm.convert the given concentration so that it uses cm⁻³.we can use conversion factors. we have to cube our conversion factors so that dimensional analysis works.we can convert to meters first, using the fact that     10 dm = 1 m  ⇔ 10³ dm³ = 1 m³then we use the fact that     10² cm = 1 m ⇔ (10² cm)³ = (1 m)³ ⇔ 10⁶ cm³ = 1 m³so converting:     now we have to find the moles of hydrochloric  acid neededfind the moles of calcium carbonate. we have to find the molar mass of calcium carbonate, caco₃, which can be found by    molar mass = (mass ca) + (mass c) + 3(mass o)    = 40 + 12 + 3(16)    = 100 g/molconvert the given 5 g to moles:     mol caco₃ = 5 g caco₃ * 1 mol/(100 g) = 0.05 mol caco₃use stoichiometry (ratios) to figure out the moles of hcl needed. ratio wise, there's 2 hcls for every caco₃, so use dimensional analysis    mol hcl = mol caco₃ * (2 mol hcl) / (1 mol caco₃)    = 0.05 mol hcl * 2    = 0.1 mol hcl  we have 0.1 mol hcl and concentration of hcl (0.002 mol/cm³).we need to find volumesince concentration = moles / volume, rearrange to get     volume = moles / concentration    volume = 0.1 mol / (0.002 mol/cm³)    volume = 50 cm³