A gas has its pressure decrease from 760 torr to 320 torr at 225k. Was is the initial temperature of the gas?

Explanation:

Given the following data;

Final pressure, P2 = 760 Torr

Initial pressure, P1 = 320 Torr

Final temperature, T2 = 225K

To find the initial temperature, we would use Gay Lussac's law;

Gay Lussac law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

Making T1 as the subject formula, we have;

Substituting into the equation, we have;

Therefore, the initial temperature of the gas is 94.75 Kelvin.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2