A ring of pure gold has a mass of 17.3 grams. How many atoms of gold are in the ring?

5.29936 x 10^23 atoms

Explanation:

To do this, we need to find the number of moles in the ring so that we can then multiply that by Avogadro's number (6.022×10^23).

equation for finding moles:

substitute in the known values:

divide to find the value of n: 0.088 mol

Multiply by Avogadro's constant: 0.088 x 6.022 x 10^23

= 5.29936 x 10^23 atoms in the ring.

hope this helps!

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

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the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.