Determine el volumen de las siguientes figuras: Un cubo de 3.5 cm. De lado. Una esfera de 5.8 cm. De diámetro. Cubo A= l 3 Esfera A = 4 π R 2

42.875cm³ ; 422.73 cm³

Explanation:

Given that:

Volume of a cube (V) = a³

a = 3.5cm

V of a cube = (3.5cm)^3

Volume of a cube = 3.5cm * 3.5cm * 3.5cm

Volume of a cube = 42.875cm³

Volume of a Sphere, V = 4πR²

V = 4 * π * 5.8²

V = 4 * π * 33.64

V = 422.73270

V = 422.73 cm³

11 players on a field that has a maximum of 11 players

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :