How many moles of SnO2 would need in order to produce 8.67 moles of Sn?

8.67 mol SnO₂

Explanation:

Step 1: Write the balanced equation for the decomposition reaction of SnO₂ to produce Sn

SnO₂(s) ⇒ Sn(s) + O₂(g)

Step 2: Establish the appropiate molar ratio

According to the balanced equation, the molar ratio of SnO₂ to Sn is 1:1.

Step 3: Calculate the moles of SnO₂ required to produce 8.67 moles of Sn

We will use the established molar ratio.

8.67 mol Sn × 1 mol SnO₂/1 mol sn = 8.67 mol SnO₂

the answer for sodium is 0.186

the answer for rubidium is 0.251