When 86.0 mL of 5.00 M sulfuric acid react with 345 mL of 3.80 M sodium hydroxide, what mass of water forms?
HS0, + NaOH
Na, SO+ H2O

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explanation:

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"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

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i think? ?