Answers: 1
for the acid is 
= 2.031
![[H^+]=c\times \alpha](/tpl/images/1121/0617/4fc41.png)
![[H^+]=0.500\times 0.030=0.015](/tpl/images/1121/0617/28636.png)
![pH=-log[H^+]](/tpl/images/1121/0617/15713.png)
![2.031=-log[H^+]](/tpl/images/1121/0617/0b1a6.png)
![[H^+]=0.009](/tpl/images/1121/0617/13241.png)
![[H^+]=c\alpha](/tpl/images/1121/0617/21a04.png)
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In the laboratory, a general chemistry student measured the pH of a 0.313 M aqueous solution of acet...
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