Upload a file with your answers to this question. Your upload MUST be ONE FILE. 1) (1 point)
In a normal distribution, what proportion of scores fall between z= -1.25 and z= 2.75. (Sketch the
distribution to show your work).
2) (1 point)
Intelligence quotient (IQ) scores are normally distributed with a mean of 100 and a standard
deviation of 15. If everyone I meet claims that their IQ is above 145, should I feel skeptical about the
likelihood that most people have IQs at this level?
Explain your answer by drawing the sketch and describing the proportion of people with IQs
above 145.
3) (1 point)
In her math class, Kim received a 75 on her test (mean for the class was 80 and standard deviation
was 3). Her friend Pat took a test on the same day in her english class and earned a 60 (mean for the
class was 55 and standard deviation was 2). Kim is bragging that she did better relative to her
classmates than Pat because her score was higher. Is she correct?
Explain your answer by providing sketches and z-scores.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

here are some of the ways in which chemical and nuclear reactions differ.

explanation: