Chemistry, 17.02.2021 08:40 MrSavannahCat
100 cm3 of 0.025 moldm-3
lead (II) nitrate solution react with 100 cm3 of 0.025 moldm3 sodium sulphate solution at temperature of 30.0◦C. a white precipitate was formed,
and the highest temperature reached is 36.0◦C. calculate the heat of precipitation.
(c= 4.2 Jg-1
◦C ; density of solution = 1gcm-3
)HELPPP
Answers: 3
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100 cm3 of 0.025 moldm-3
lead (II) nitrate solution react with 100 cm3 of 0.025 moldm3 sodium sulph...
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