1) If 6.00 grams of gaseous hydrogen reacts with 16.0 grams of gaseous oxygen to form water vapor, a) Write and balance the chemical equation.
c) determine the grams of gaseous water

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

2b2t

explanation:

2b2t