Gaseous butane CH3CH22CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. Suppose 0.58 g of butane is mixed with 0.874 g of oxygen. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits.

0.378 g of H₂₂O can be produced.

Explanation:

The combustion reaction is:

2CH₃(CH₂)₂CH₃  +  13O₂  →  8CO₂  +  10H₂O

We convert the mass of reactants to moles:

0.58 g . 1mol / 58.1g = 0.00998 moles of butane

0.874 g . 1mol / 32g = 0.0273 moles of O₂

Oxygen is the limiting reactant. Look at stoichiometry.

2 moles of butane need 13 moles of oxygen to react

Then, 0.00998 moles of gas may react to (0.00998 . 13) / 2 = 0.06487 moles of oyxgen. I only have 0.0273 moles, so i do not have enough oxygen to complete the reaction.

Let's find out the product.

13 moles of oyxgen can produce 10 moles of water.

Then 0.0273 moles of O₂ may produce (0.0273 . 10)/13 =  0.021 moles

We convert to mass  →  0.021 mol . 18g /1mol = 0.378 g

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.