1. What percentage of the solution is formed from 80g HCl and 230g water?

2. What is the volume of a solution with a substance concentration of 1 M
(1 mol / dm3) can be prepared from 156 g KOH?

3. How many grams of 9% HCl need to be added to 340g of 50%
solution of the same acid to form a 25% solution?

43.452

step-by-step explanation:

284 times .153 = 43.452

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"