A 51.1g sample of brass is put into a calorimeter (see sketch at right) that contains 250.0g of water. The brass sample starts off at 95.4°C and the temperature of the water starts off at 25.0°C. When the temperature of the water stops changing it's 26.4°C. The pressure remains constant at 1atm. Required:
Calculate the specific heat capacity of brass according to this experiment.

0.415 j/g°C

Explanation:

Given that :

Mass of water, m1= 250.0 g

Temperature of water, T1= 25°C

Specific heat capacity of water, C= 4.184 J/g°C

Mass of brass , m2= 51.1g

Temperature of brass = 95.4°C

Specific heat capacity of brass , c2=?

Final temperature = 26.4°C

Heat lost by brass = Heat gained by water

mc(dT) = mc(dT)

51.1 * c * (95.4 - 26.4) = 250 * 4.184 * (26.4 - 25)

51.1 * 69 * c = 250 * 4.184 * 1.4

3525.9c = 1464.4

c = 1464.4 / 3525.9

c = 0.4153265

c = 0.415 j/g°C

Specific heat capacity of Brass for the experiment = 0.415 j/g°C

what does the table look like