A student increases the temperature of a 200 cm balloon from 60°C to 120°C. What will the new volume of the balloon be?
A)100cm^3
B)200cm^3
C)263cm^3
D)400cm^3

236 cubic cm

Explanation:

We are given that

Initial volume, V1=200 cubic centimeter

Initial temperature, T1=60 degree Celsius=60+273=333 K

Final temperature, T2=120 degree Celsius=120+273=393 K

Kelvin temperature=Celsius temperature+273

We have to find the new volume of the balloon.

We know that

Charles's law

Using the formula

Hence, the new volume of the balloon will be 236 cubic cm.

first one is the correct answer

i think it's c. i'm not sure but i think so.