A sample of Oxygen gas is in a cylinder at constant temperature. What would happen to the pressure of the gas if the volume was smooshed down to half its original size? Decreasing the volume by a factor of 2.

This means that the pressure would become double of it's initial pressure.

Explanation:

Key statements:

- Constant temperature

- What happens to the pressure of the gas if the volume was

smooshed down to half its original size?

Basically the question is asking about the relationship between pressure and volume at constant temperature. This is given by Boyle's law.

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to it's volume at a fixed temperature.

This is given by;

P1V1 = P2V2

Where;

P1 = Initial pressure

P2 = Final pressure

V1 = Initial Volume

V2 = Final Volume

From the question;

V2 = V1/2

Inserting it into the equation;

P1 V1 = P2 V1/2

Divide all through by  V1

P1  = P2 /2

P2 = 2 P1

This means that the pressure would become double of it's initial pressure.

the answer is 1 i believe