2NH3+2O2- N2o+3H2O If 80.0 grams of O2 are reacted in the above reaction, how many grams of N2O will be produced?

55.025g of N2O

Explanation:

2 NH3 + 2 O2 → N2O + 3 H2O

moles of O2 = 80.0/32 = 2.5 moles O2

moles of N2O = 2.5 moles O2 * 1 mole N2O

= 1.25 moles N2O

moles = mass/Molar mass

mass = moles * Molar mass = 1.25 x 44.02 = 55.025 g