The equilibrium constant, K, for the reaction
N204(9) = 2 NO2(g)
at 25°C is 5.88 x 10-3. Supp...
Chemistry, 21.02.2021 01:40 thomascoop85
The equilibrium constant, K, for the reaction
N204(9) = 2 NO2(g)
at 25°C is 5.88 x 10-3. Suppose 15.6 g of N204 is placed in a 5.00 L flask at 25°C. Calculate:
(a) The number of moles of NO2 present at equilibrium
(b) The percentage of the original N20, that is dissociated
Answers: 1
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