If the temperature of a gas is 27.0°C when the volume is 1.25 L, what will the new volume be if the temperature is raised to 150°C?

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Explanation:

0.17166666666

Explanation:

New volume V2 = 1.7625 L

Explanation:

Given:

Old temperature T1 = 27°C = 27 + 273 = 300 K

Old volume V1 = 1.25 L

New temperature T2 = 150°C = 150 + 273 = 423 K

Find:

New volume V2

Computation:

V1 / T1 = V2 / T2

1.25 / 300 = V2 / 423

New volume V2 = 1.7625 L

a polar bond is formed when electrons are shared unevenly between atoms

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole