Based on the following equation, how many moles of hydrochloric acid (HCl)are needed to react with 0.44 moles of potassium permanganate (KMnO4)?
2KMnO4 + 8HCI - 3Cl2 + 2MnO2 + 4H2O + 2KCI

1.76 moles of HCl.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KMnO₄ + 8HCl —> 3Cl₂ + 2MnO₂ + 4H₂O + 2KCl

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Finally, we shall determine the number of mole of HCl needed to react with 0.44 moles of KMnO₄. This can be obtained as follow:

From the balanced equation above,

2 moles of KMnO₄ reacted with 8 moles of HCl.

Therefore, 0.44 moles of KMnO₄ will react with = (0.44 × 8)/2 = 1.76 moles of HCl.

Thus, 1.76 moles of HCl is needed for the reaction.