Moles of zn(no3)2 in 131.50g of this substance.

The quantity of moles in 131.50g of Zn(NO3)2 is 0.6943

Explanation:

Using the equation:

Moles = mass/ molecular mass

Moles Zn(NO3)2 = mass Zn(NO3)2 / molecular mass Zn(NO3)2

mass Zn(NO3)2 = 131.50g

molecular mass Zn(NO3)2 is calculated by looking at the atomic mass of each element in the periodic table, then multiplying by the number on the compound's formula:

Zn= 65.38 g/mol

N= 14 g/mol

O= 16 g/mol

molecular mass Zn(NO3)2 = Zn + 2*N + 2*3*O =65.38 + (2*14) + (2*3*16)

molecular mass Zn(NO3)2 = 189,38 g/mol

Moles Zn(NO3)2 = 131.50g / 189,38 g/mol

Moles Zn(NO3)2 = 0.6943

i think it is d. e because the next one is igneous.

c, liquids evaporate, creating a gas