2. How many grams of methane must be burned to produce 2.05 grams of water in the complete combustion reaction? The unbalanced equation for the reaction is: _CH418) + _ 0218) ►_CO2(8) +_ H2O(8)

0.88 g

Explanation:

The balanced reaction equation is;

CH4(g) + 2O2(g) > CO2(g) + 2H2O(l)

Number of moles in 2.05g of water = 2.05g/18g/mol = 0.11 moles

If 1 mole of CH4 yields 2 moles of water

x moles of CH4 yields 0.11 moles of water

2x = 0.11

x = 0.11/2

x= 0.055 moles

Molar mass of methane = 16 g/mol

Mass of methane = 16 g/mol * 0.055 moles

Mass of methane =0.88 g

indicate valleys, hills, steepness and gentleness of slopes.

explanation:

contour lines on a map indicate elevation, or depth. numeric notations on contour lines refer to the level of elevation, or height about sea level.

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.