on analysis an ammonium salt of an alkanoic acid gave 60.5% C and 6.5% H if 0.309g of the salt yield 0.0313g of Nitrogen determine the empirical formula of the salt [ H = 1, C =12, N = 14, O= 16]​

C7H9NO2

Explanation:

%N = 0.0313/0.309 x 100

= 10.1%

%0 = 100 — (60.5 + 6.5 + 10.1)

= 22.9

C; 60.5/12 H; 6.5/1 N; 10.1/14 O; 22.9/16

C; 5.04/0.72 H; 6.5/0.72 N; 0.72/0.72 O; 1.43/0.72

Empirical formula — C7H9NO2

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.