Chemistry, 25.02.2021 23:50 PinkDivaGirl02
Fe2(SO4)3 + 6NaCl = 2FeCl3 + 3Na2SO4 How many moles of sodium chloride will react fully with 12.7 moles of iron (III) sulfate?
Answers: 3
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Each step in the following process has a yield of 70% ch4 + 4cl2 yield ccl4 +4hcl ccl4 + 2hf yield ccl2f2 + 2hcl of 4.50 mole ch4 reacts what is the total amount of hcl produced
Answers: 3
Fe2(SO4)3 + 6NaCl = 2FeCl3 + 3Na2SO4
How many moles of sodium chloride will react fully with 12.7 m...
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