How many moles of Mg3(PO4)2 are in 350.00 grams of Mg3(PO4)2?

1.3 moles/ 1.33150727 moles

Explanation:

350g x 1 mol/262.86g = 1.3 moles

The molar mass of Mg3(PO4)2 is 262.855 g/mol

Atomic weight of the parts:

Mg24.3050   x 3 = 72.92

P30.973762   x2 = 61.95

O15.9994   x8 = 127.995

There are 262.855 grams in one mole, so  

350.00 g x (262.855g/1 mole) = 1.33 moles Mg3(PO4)2

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