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3CaCl2(aq) + 2Na3(PO4)(aq) → Ca3(PO4)2(s) + 6NaCl(aq)
Use the balanced equation and the Molar Mass table above to answer the following question.
Suppose 163.9 g of Na3(PO4) reacted with sufficient CaCl2 in solution to actually yield 116 g of Ca3(PO4)2(s) . What is the percent yield of Ca3(PO4)2(s)?
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You know the right answer?
3CaCl2(aq) + 2Na3(PO4)(aq) → Ca3(PO4)2(s) + 6NaCl(aq)
Use the balanced equation and the Molar Mass...
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