2. Calculate AH for the reaction 2C2H6(g) + 702(g) + 4CO2(g) + 6H2O(1)
delta H = ?
Given:
CzH(g) + 302(g) → 2C02(g) + 2H2O(1) delta H = -337.2kcal
C2H2(g) + H2(g) → CyH6(9) delta H = - 32.7 kcal
H2(g) + 1/2O2(g) → H2O(l)
delta H = - 68.3 kcal

1 is the answer to this problem

pv=nrt

explanation:

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.