One method of producing calcium carbonate is a two step process that begins with the synthesis reaction of calcium oxide with water to produce calcium hydroxide. The second step reacts calcium hydroxide with carbon dioxide to produce the calcium carbonate and water. CaO + H2O → Ca(OH)2

Ca(OH)2 + CO2 → CaCO3 + H2O

If in the first step 18.2 grams of CaO are reacted with excess water and after reaction 85.4% of the theoretical yield of Ca(OH)2 was recovered, what is the theoretical yield, in grams, of the calcium carbonate? Assume excess CO2 in step 2.

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the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

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for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

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