Directions: Using the words inside the box, fill in the blanks to complete the thought of the paragraph. There are six main requirements for a typhoon to form and develop. It needs an abundance of (1). The (2) must have a temperature of 26.5ºC spanning from the surface up to a depth of at least 50 meters (160 ft.) or more. Another requirement is to have too much water vapour present in air known as (3). The low vertical wind shear also contributes to the formation of typhoon. It also needs an (4) for typhoon development which is 500 km (300 mi) from the equator. The (5) causes the powerful wind to spin at this particular region. If any one of these requirements were below average or minimum, a tropical cyclone would not form.​

The continuous release of nuclear energy caused when one fission reaction triggered more nuclear reactions is a

0.09 moles of sodium sulfate in 12 ml of solution

Ineed someone to see if my answers are correct! if any are wrong let me know what the correct answers would be and how to get that answer! 1. how many moles of sodium chloride are in 28 grams od nacl? a. 265 mole naclb. 856 mole naclc. 479 mole of nacld. 1.2 mole nacl < my choice2. 734 grams of lithium sulfate (li2so4) are dissolved to make 2500 ml of solution what is rhe molaratiy? a. 2.67 mb. 4.56 mc. 3.89 m < my choiced. 1.78 m3. how many grams of cacl2 would be dissolved in 3.0 l of a 0.50 m solution of cacl2? a. 250 g cacl2 b. 166.5 g cacl2c. 113.65 g cacl2d. 98 g cacl2 < my choice4. suppose you had 58.44 g of nacl and you dissolved it in exactly 2.00 liters. the molarity if the solution would be 0.5 mtrue < my choicefalse 5. i would need 22g of naoh to make a 3.0 m solution using 250 ml of solvent.true < my choicefalse6. identify the solute: you have a .0195 m solution made from using 6.5 g of solute and 3 l of solvent. identify the solute by solving for molar weight.a. the solute is nacl because the molar weight is 58.43 g/mol < my choiceb. the solute is h2so4 because the molar weight is 98.06 g/molc. the solute is cacl2 because the molar weight is 111.11 g/mol