iron (III) oxide is formed when Iron combines with oxygen gas. how many grams of iron (III) oxide are formed when 16.7 g of iron metal reacts with excess oxygen gas? (show work)​

C) electrons encircling a nucleus with neutrons and protons

The net force is 100

Mv^2 is a conserved quantity so v goes as sqrt(1/m) heavier is slower 64/4 = 16 sqrt(16) = 4

Answer is: mass of hydrochloric acid is 4,08 grams.chemical reaction: 2hcl + mg(oh)₂ → mgcl₂ + 2h₂o.m(mg(oh)₂) = 3,26 g.n(mg(oh)₂) = m(mg(oh)₂)  ÷ m(mg(oh)₂).n(mg(oh)₂) = 3,26 g  ÷ 58,32 g/mol.n(mg(oh)₂) = 0,056 mol.from chemical reaction: n(mg(oh)₂) : n(hcl) = 1 : 2.n(hcl) = 2  · 0,056 mol = 0,112 mol.m(hcl) = 0,112 mol  · 36,45 g/mol.m(hcl) = 4,08 g.