What is the mole percent of ethanol (C2H5OH), which consists of 71.0 g of ethanol for every 18.6 g of water present?A. 87.7%.B. 22.1%.C. 26.5%.D. 73.5%.E. 71.0%.

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

Explanation:

Mole percent is the percentage of the total moles that is of a particular component.

We have to covert the ethanol and water to moles. This is given by the equation;

Number of moles =  Mass / Molar mass

Ethanol;

Number of moles = 71 / 46.07  = 1.5411 mol

Water;

Number of moles = 18.6 / 18  = 1.033 mol

Total mol = 1.5411 mol + 1.033 mol =  2.5741 mol

Mole percent of Ethanol = Number of moles /(Ethanol) / Total moles   * 100

Mole percent of Ethanol =  1.5411 mol / 2.5741 mol   * 100

Mole percent of Ethanol = 0.5986 * 100 = 59.86%

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