Calculate the volume in mL of 0.100 of CaCl2 needed to produce 1.00 g of CaCO3. there is an excess of Na2CO3

100. mL

Explanation:

The computation of the volume in mL is shown below:

The balance equation of the double displacement reaction is

Now determine the moles that corresponding to 1.00 g of CaCO₃

As,

The molar mass of CaCO₃ is 100.09 g/mol.

So,

= 1.00 g × 1 mol/100.09 g

= 0.0100 mol

Now

the moles of CaCl₂ needed to generate 0.0100 moles of CaCO₃

As we know that

The molar ratio of CaCl₂ to CaCO₃ is 1:1.

So, The moles of CaCl₂ needed is

=  1 ÷ 1 × 0.0100 mol

= 0.0100 mol.

Now volume of 0.100 M CaCl₂ that contains 0.0100 mol is  

= 0.0100 mol × 1 L/0.100 mol × 1000 mL/1 L

= 100. mL

the answer is   c.) 1575 j.

explanation:

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: