A solution of 0.220 g of KIO3 is prepared in 50 ml volumetric flask. 2.00 mL of this solution is pipetted into a beaker with 8.00 ml distilled water, to give 10 ml of diluted KIO3. To this, 10.00 mL of starch sulfite was added. What would be the initial concentration of IO3- in this final solution

0.00044 g/mL

Explanation:

First, 0.220 g of KIO₃ are dissolved in 50 mL, so the concentration at this point is:

Then 2.00 mL of this solution are added to 8.00 mL of water (final volume = 10.00 mL). We calculate the concentration of the resulting solution:

Finally, to this 10 mL solution, another 10.00 mL were added. Thus the KIO₃ (or IO₃⁻) concentration is:

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

dynamic equilibrium is the answer.