A 130 g sample of brass at 120.0 degrees Celsius is placed in a calorimeter cup that contains 130 g of water at 35.0 degrees Celsius. Disregard the absorption of heat by the cup and
calculate the final temperature of the brass and water. Specific heat of water = 4.18 J/gC,
specific heat of brass=0.380 J/gC. Attach your complete solution

Explanation:

Hello there!

In this case, since we are looking for an equilibrium temperature, we can evidence how the net heat flow is 0 as all the heat released by the hot brass is absorbed by the water:

Thus, by writing that equation in terms of mass, specific heat and temperature we obtain:

Thus, by applying the following algebra, it is possible to arrive to a clean expression to obtain the equilibrium temperature:

Then, by plugging the masses, specific heats and initial temperatures in, we obtain:

Best regards!

a corroding iron, if that's one of your choices