For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
2 kclo3(s) → 2 kcl(s) + 3 o2(g)
2.72 g kclo3
0.361 g kclo3
83.6 kg kclo3
22.5 mg kclo3

Answer :

The mass of oxygen form from 2.72 g is 1.06 grams.

The mass of oxygen form from 0.361 g is 0.141 grams.

The mass of oxygen form from 83.6 kg is 32.7 kilograms.

The mass of oxygen form from 22.5 mg is 8.81 milligrams.

Explanation :

The given chemical reaction is:

Molar mass of = 122.55 g/mol

Molar mass of = 32 g/mol

For 2.72 g :

From the balanced chemical reaction we conclude that,

As, grams of decomposes to give grams of

So, grams of decomposes to give grams of

Thus, the mass of oxygen form from 2.72 g is 1.06 grams.

For 0.361 g :

From the balanced chemical reaction we conclude that,

As, grams of decomposes to give grams of

So, grams of decomposes to give grams of

Thus, the mass of oxygen form from 0.361 g is 0.141 grams.

For 83.6 kg :

From the balanced chemical reaction we conclude that,

As, grams of decomposes to give grams of

So, of decomposes to give of

Thus, the mass of oxygen form from 83.6 kg is 32.7 kilograms.

For 22.5 mg :

From the balanced chemical reaction we conclude that,

As, grams of decomposes to give grams of

So, of decomposes to give of

Thus, the mass of oxygen form from 22.5 mg is 8.81 milligrams.

16

explanation:

the marks go by 4s