For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
2 kclo3(s) → 2 kcl(s) + 3 o2(g)
a. 2.72 g kclo3
b. 0.361 g kclo3
c. 83.6 kg kclo3
d. 22.5 mg kclo3

Explanation:

Molar mass of = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of = 32.0 g

According to the equation, 2 moles of reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of as follows.

        of

(b) Calculate the amount of oxygen given by 0.361 g of as follows.

    of

c) Calculate the amount of oxygen given by 83.6 kg as follows.  

    of

Convert kg into grams as follows.

    = 32731 g of

(d) Calculate the amount of oxygen given by 22.5 mg of as follows.  

Convert mg into grams as follows.

  of

the answer is 0.42 is that is an option. this question provides no info