If 16.4 g of oxygen gas react with excess hydrogen, how many moles of water are produced? 2H2(g) + O2(g) → 2H2O(g)

1.02 (or 1.03 if rounded)

Explanation:

Given 16.4 grams of oxygen gas, you would want to write that down to set up your unit conversions.

16.4 g O2/1 * 1 mol of O2/31.998 g O2 * 2 mol H2O/1 mol O2

Multiply the numbers on the top and divide that by the product of the numbers on the bottom.

16.4 * 1 * 2 = 32.8

1 * 31.998 * 1 = 31.998

32.8/31.998 = 1.025...

Don't forget to consider the number of significant figures if it asks!

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.