Which conversion factor below would you use to complete this conversion? How many liters of bromine gas would 12.3 moles occupy at Standard Temperature and Pressure?

a.) 1 mole/22.4 L
b.) 22.4 mol/1 liter
c.) 22.4 L/1 mole
d.) 1 liter/22.4 mol

c.) 22.4 L/1 mole

Explanation:

Using the general gas law equation as follows:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

The standard values for a gas are as follows:

Standard pressure of a gas = 1 atm

Standard temperature of a gas = 273K

According to the information in the question, n = 12.3 moles

Using PV = nRT

V = nRT/P

V = 12.3 × 0.0821 × 273/1

V = 275.68 L

Based on this value of volume in liters for 12.3moles of Br gas, the volume per mole at standard temperature and pressure will be 275.68/12.3 = 22.4 Litres per mole. Hence, the answer is 22.4 L/1 mole.

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