What is the number of moles in 125ml of 0.25 M NaNO3solution?

0.0313 mole.

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 125 mL

Molarity of NaNO₃ = 0.25 M

Number of mole of NaNO₃ =?

Next, we shall convert 125 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

125 mL = 125 mL × 1 L / 1000 mL

125 mL = 0.125 L

Thus, 125 mL is equivalent to 0.125 L.

Finally, we shall determine the number of mole of NaNO₃ in the solution. This can be obtained as follow:

Volume of solution = 0.125 L.

Molarity of NaNO₃ = 0.25 M

Number of mole of NaNO₃ =?

Molarity = mole / Volume

0.25 = mole of NaNO₃ / 0.125

Cross multiply

Mole of NaNO₃ = 0.25 × 0.125

Mole of NaNO₃ = 0.0313 mole.

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