What mass of iron is formed when 240 g of iron(III) oxide reacts completely with carbon monoxide?

168 g

Reaction:

Explanation:

First we need to figure out what is the formula mass (Mr) of Fe2O3 (Iron(III) oxide).

The atomic mass of Fe=56, O=16

Mr= 56+56+16+16+16=160 g/mol

We can now figure out the moles of the iron:

240/160 = 1.5 mol

Then we need to find the ratio to make Fe.

In the reaction, we know that 1 mole of Fe2O3 can make 2 moles of Fe. So 1.5 moles of Fe2O3 can make 3 moles of Fe.

And then we need to find the mass of the Fe.

3×56=168 g.

Hence 168g of the iron is made after the reaction.