If 23.2 g of a given gas occupies a volume of 93.2 L at a particular temperature and pressure, what mass of the gas occupies a volume of 10.4 L under the same conditions?

2.59g

Explanation:

Using Avagadro's law equation as follows:

V1/n1 = V2/n2

Where;

V1 = initial volume (litres)

V2 = final volume (litres)

n1 = first amount of gas in grams

n2 = second amount of gas in grams

According to the information provided in this question, v1 = 93.2L, v2 = 10.4L, n1 = 23.2 g, n2 = ?

Using V1/n1 = V2/n2

93.2/23.2 = 10.4/n2

Cross multiply

93.2 × n2 = 23.2 × 10.4

93.2n2 = 241.28

n2 = 241.28/93.2

n2 = 2.588

n2 = 2.59g

c, liquids evaporate, creating a gas