Calculate the mass of 15.0 L of NH3 at 27° C and 900.0 mm Hg (the molar mass of NH3 is 17.04g/mol). *Remember the value for your Ideal Gas Constant, the units of measurement needed for each value BEFORE trying to show calculate, and remember your conversions and T-chart*

i think so it’s will be b yes i believe its

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o