CO + 2H2 ⇌ CH3OH ΔH <0 The synthesis of CH3OH(g) from CO(g) and H2(g) is represented by the equation above.

Which of the following statements is true about bond energies in this reaction?

a. The energy absorbed as the bonds in the reactants are broken is less than the energy released as the bonds in the product are formed.
b. The energy released as the bonds in the reactants are broken is less than the energy absorbed as the bonds in the product are formed.
c. The energy released as the bonds in the reactants are broken is greater than the energy absorbed as the bonds in the product are formed.
d. The energy absorbed as the bonds in the reactants are broken is greater than the energy released as the bonds in the product are formed.

C. The energy released as the bonds in the reactants are broken is greater than the energy absorbed as the bonds in the product are formed.

Explanation:

As ΔH is negative, the given reaction is exothermic.

That means that the enthalpy of the product is less than the enthalpy of the reactants. In other words, part of the energy from the reactants is used to form new bonds (between C and H, for example), while the other part is transfered outside the system as heat.

Thus the correct answer is C.

може ли да зареждате повече информация, моля

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.